Correct answer: Bb71...Rb7/Bc6 2.Qc6# 1...Rb3+/Rc8/Rd8/Re8/Rf8/Rg8/Rh8/Bb7 2.Q:b3# 1.Bb7! (2.Qb3#/Qc6#) 1...R:b7 2.Q<