Correct answer: Rf41...Qg4[a]/Qh7[a] 2.B:f6#[A] 1...Q:e4/[б]/ 2.Qb6#[Б] 1...B:e4[c] 2.Qg1#[D] 1...Bd5/Bc8[d]/Ba6[e] 2.R:d5#[C] 1...Nh5[f]/Ne2[f] 2.B