Correct answer: Qg11...Bg6[a]/f4/[б]/ 2.Q:b2#[A] 1...Bg7[c] 2.Qc6#[Б] 1...h5 2.Qg5# 1...Ne7 2.Rd6# 1.Rc7? zz 1...f4/[б]//Bg6[a] 2.Q:b2#[A] 1...Bg7[c] 2.