Correct answer: e:d71...B:e6/e:f6 2.Qg3# 1...Bb2/Bc1 2.c5# 1.f:e7[A]? (2.Qg3#) 1...Bg2[a] 2.e:d7#[Б] 1...Bb2/Bc1 2.c5# 1...Rf8 2.e:f8Q#/e:f8B# but 1.