Correct answer: Kg41...B:e3+[a] 2.R:e3#[A] 1...Ng3/Ng7/Nf4/Nf6/[б]/ 2.Rf4#[Б] 1...B:f3[c]/Bd1 2.Bd3#[C] 1...R:d5+ 2.B:d5# 1...Bd3 2.B:d3#[C]/c:d