Correct answer: Bg21...e5[a] 2.Ng5#[A] 1...N5d3/[б]/ 2.N:c3#[Б] 1...Nd7[c]/N5b3[c]/Nb7[c]/Na6[c] 2.Nf2#[C]/N:c3#[Б] 1...Na4[d] 2.Nf2#[C] 1.B:c5? (2.N