Correct answer: Qb81...e6[a] 2.Qd3#[A] 1...e5/[б]/ 2.Qd7#[Б] 1.Qb6? zz 1...e5/[б]/ 2.Q:f6#[C] 1...f:g5[c] 2.R:f7#[D] but 1...e6[a]! 1.Qe2?? zz 1...e6[a] 2.Qd3#[A] 1...
