Correct answer: Nhf51...Kf4[a]/Kf6/[б]/ 2.Q:d6#[A]/Q:d4#[Б] 1.Ra6? (2.Q:d6#[A]) 1...Kf6/[б]/ 2.Q:d4#[Б] but 1...d3! 1.Rd7? (2.Q:d6#[A]) 1...Kf4[a] 2.