Correct answer: Ne51...Bd3[a] 2.Be3#[A] 1...Bc4/[б]/ 2.Qb6#[Б] 1...d5[c] 2.Qc5#[C] 1.Qc6? zz 1...Bd3[a] 2.Be3#[A] 1...Bc4/[б]/ 2.Qb6#[Б] 1...d5[c] 2.Q