Correct answer: Qd71...Bf6[a] 2.Nf7#[A] 1...Nd5/[б]/ 2.Q:d5#[Б] 1...Be7/Bb6/Ba5 2.Q:e7# 1...Nd1/Ne2/Nb1/Nb5/Na2 2.Qb5#/Qd5#[Б] 1.Q<