Correct answer: Q:a71.Qd8? 2.Be6#[A] 1...d6 2.Q:d6# but 1...d3[a]! 1.Qd2? 2.e4#[Б] 1...d3 2.Q:d3# but 1...d6/[б]/! 1.Q:a7! (2.Nb6#) 1...d6/[б]/ 2.Be6#[A] 1...d
