Correct answer: Ncd51...e:f5+[a] 2.N:g8#[A] 1...e5+/[б]/ 2.d5#[Б] 1.Nb5? (2.d5#[Б]/Nd6#[C]) 1...f3/e:f5+[a]/e5+/[б]/ 2.d5#[Б] 1...c2 2.Nd6#[C] but 1...a:b5! 1.N:a6? (2.d5#[Б]) 1...b5 2.<
