Correct answer: Kd71.Kd7! (2.c4#/e4#/Q:d4#/Qh1#) 1...Qg6/Qh7/Re5 2.c4#/Q:d4# 1...f5 2.Qh1#/c4# 1...Ra1/Bg3/Bg5 2.c4#/Q:d4#/e4# 1...R:a6/