Correct answer: Q:c71...K:g2[a] 2.Qc2#[A] 1...h:g2/[б]/ 2.Qh6#[Б] 1...e3[c] 2.Rh1#[C] 1.Qc2[A]? (2.Rh1#[C]/Bh1#/Bf3#/B:e4#) 1...e3[c] 2.Rh1#[C] but 1...h:g2/[б]/!
