Correct answer: Rd71...Ne3 2.f:e3#[A] 1.Rg4? (2.Rd6#) 1...Nc4[a]/Be7[c] 2.Nf3#[Б] 1...Nd3/[б]/ 2.R:e4#[C] 1...N:f6 2.B:f6# but 1...Bf8+! 1.R