Correct answer: Qc71...B:b2[a] 2.Q:b2#[A] 1...Rd6/[б]//Rd8[c]/R:c5[d] 2.Qe4#[Б] 1...R:e5[e] 2.Rd3#[C] 1...Ng2/Ng6/Nf3/Nf5 2.Nf3# 1...Nb5/N