Correct answer: Kd51...Nb1/Nb5/Nc2/Nc4[a] 2.Kb5#[A] 1...Ng6/[б]//Nh7/Ne6/Nd7/[б]/ 2.Kd7#[Б] 1...b5 2.Kc5# 1...Bc7 2.K:c7# 1...e:d6 2.K:d6#
