Correct answer: Nc21...Ke5[a] 2.Re6#[A] 1...Kf3/[б]//Nd3 2.Bc6#[Б] 1...Kd3[c]/Ng2/Ng6/Ne2/Ne6/Nd5 2.Nf2#[C] 1.Bc6+[Б]?? 1...Kd3[c]/N