Correct answer: e:f61...Be4[a]/Bb7/[б]//Ba8/[б]/ 2.Rd6#[A] 1...Be7[c] 2.R:e7#[C] 1...B:c7[d] 2.Q:f6#[D] 1...Bc6+/c:d3 2.R:c6#[Б] 1.Kb4? zz 1...Be4[a]/
