Correct answer: Rd21...Ne1[a]/Ne3/[б]//Na1[c]/Na3[c] 2.Qe3#[A] 1...d:e4[d] 2.R:e4#[Б] 1...B:d3[e] 2.Q:e5#[C] 1...b6/b5 2.Nc6# 1...Bb5/Ba6 2.N:b3# 1.R<