Correct answer: Qh51...Ne6/Nf7[a] 2.Q:a8#[A] 1...e:d6/[б]/ 2.Qe4#[Б] 1...e5[c] 2.Q:e5#[C] 1.Qh8? (2.Qe5#[C]) 1...Nf7[a] 2.Q:a8#[A] 1...e:d6/[б]/ 2.Nc7#[D] but
