Correct answer: Nd81...e6[a] 2.Qc6#[A] 1...B:b7/[б]/ 2.Q:d7#[Б] 1...d6+[c] 2.c:d6#[C] 1.Ba6? zz 1...B:b7/[б]/ 2.Q:b7#[E] 1...d6+[c] 2.Q:d6#[D] but 1...e6[a]! 1.Qe4? zz
