Correct answer: Bd41...Bd3[a] 2.Rc5#[A] 1...N:c3/[б]/ 2.Rb4#[Б] 1...Nc7[c]/Nd4[d]/Nd6[c]/Na7[c] 2.Rd4#[C] 1...B:g2/Be2 2.Be2# 1...Bg3/Bh2/B