Correct answer: Qg11...Bf2[a] 2.Nd2#[A] 1...Bg3/[б]//Bd2[c]/Bc3[d]/Bb4[d]/Ba5[d] 2.Q:g3#[Б] 1...N:f4[e] 2.Q:f4#[C] 1...N:e3[f] 2.Q:e2#[D] 1...Ng6/N<