Correct answer: Bd21...N:e6/Nf3[a]/Nc6 2.Qe3#[Б] 1...N:f4 2.Nc5#[A]/Q:d4# 1...Ng1/Ng3/Nc1/Nc3 2.Q:d4# 1...B:f4 2.Nc5#[A] 1.Qc5? (2.