Correct answer: e41...Nf4[a]/Ng1[a]/Ng3[a]/Nc1[a]/Nc3/[б]/ 2.Qd4#[A] 1...Nc2[c]/Nc6[d]/Nd5[e]/Na2[c]/Na6[c] 2.Qc6#[Б] 1...Nd4 2.e:d4#/Q:d4#[A]
