Correct answer: Qb61...g6[a] 2.Qf1#[A] 1...f6/[б]/ 2.Qd3#[Б] 1...g4[c] 2.Bc2#[C] 1.Qa1? zz 1...g6[a] 2.Qe5#[D] 1...f6/[б]/ 2.Qb1#[E] 1...g4[c] 2.Bc2#[C] but 1...Kg6!
