Correct answer: N:f41...Be7[a]/Bf8[a]/Bc5/[б]//Bb4[c]/Ba3[a] 2.d6#[A] 1...g3[d] 2.N:g3#[Б] 1...f3+ 2.Q:f3# 1.Kh2? zz 1...Be7[a]/Bf8[a]/Bc5/[б]//Bb4[c]/<