Correct answer: Bd51...Nc8[a]/Nbd5/Nd7/[б]//Na4[c]/Na8/[б]/ 2.Nd7#[Б] 1...Nf1[d]/Nf5[d]/Ng4[d]/Nd1[d]/Ned5/Nc2[d]/Rd5 2.N:e4#[C] 1...d5 2.Bf8
