Correct answer: Qd31...b4[a] 2.Q:a4#[Б] 1...e5/[б]//d5[d] 2.Qc5#[C] 1...Bb3[c]/Bc2[c]/Bd1[c] 2.Qa8#[D] 1...Bc7/Bb6/Ba5 2.N:e7#[A] 1...e:f6 2.Q:d6# 1...Nb4/<
