Correct answer: Qa11...Ra1[a] 2.Q:a1#[A]/R:a1#[Б] 1...Ra7 2.Rb8# 1.Ra1[Б]? (2.R:a4#) 1...R:a1[a] 2.Q:a1#[A] 1...Ra3/[б]/ 2.R:a3#[C] 1...Ra2[c] 2
