Correct answer: Qa61...Bg6[a] 2.Qf2#[A] 1...f6/[б]/ 2.Qb1#[Б] 1.Qb2?? zz 1...Bg6[a] 2.Qf2#[A]/Qe5# 1...f6/[б]/ 2.Qb1#[Б]/Qc2# but 1...Kg6! 1.Qc6?? zz
