Correct answer: Rb31...Nf4[a]/Ng1/[б]//Ng3[c]/Nc1[c]/Nc3[a] 2.B:d4#[A] 1...Bh4[d]/Bf4[d]/Be3[d]/Bd2[e]/Bc1[e]/Bf6[f]/Be7[g]/Bd8[d] 2.R:d5#[Б]