Correct answer: Kb41...Bc7+[a] 2.Nb6#[A] 1...Bd6/[б]/ 2.Qe8#[Б] 1.Q:a7?? (2.Qb6#/Qc5#) 1...Bc7+[a] 2.Nb6#[A] 1...Bd6/[б]/ 2.Qb6#/Nd8# but 1...B<