Correct answer: Nb61...Bf5[a]/Bd3/[б]//Bc2/Bb1 2.N:c6#[Б] 1...Bf3/Bg2/Bh1/Bd5[c] 2.N:g6#[A] 1...Ng7/N:d6/Nc7 2.B:g7# 1.Kd2? (2.N:
