Correct answer: Kd71...Ke3[a] 2.Bb6#[A] 1...Kc3/[б]/ 2.Bf6#[Б] 1.Kc6? zz 1...Ke3[a] 2.Bb6#[A] 1...Kc3/[б]/ 2.Bf6#[Б] but 1...Ke5! 1.Ke6? zz 1...