Correct answer: Nb41...Ng3[a]/Nh2[a]/Ne3[a]/Nd2/[б]/ 2.Qd2#[A] 1...c:b3[c] 2.Rc5#[Б] 1...a2[d] 2.Bb2#[C] 1.Rb4? zz 1...Ng3[a]/Nh2[a]/Ne3[a]/Nd2/[б]/ 2.<
