Correct answer: Ngf21...e6[a] 2.Bc6#[A] 1...e5/[б]/ 2.Ngf6#[Б] 1...K:e4 2.Qf3# 1...Ne1/Ne3/Nb4/Na1/Na3 2.Q:d4# 1.Kh3? zz 1...e6[a] 2.Bc6#[A] 1...