Correct answer: Qa51...Rd4[a]/R:c3/[б]/ 2.Bf6#[A] 1...R:d2 2.Bf4#/Bf6#[A] 1...R:d5 2.Qe8#/Qh8# 1...Re3/Rg3/Rh3 2.Bf4#/Bf6#[A]/d4# 1...Rf3