Correct answer: Qg11.Qa1? zz 1...Kc2/[б]/ 2.Nb4#[Б] 1...Kd4/e2[c] 2.Q:c3#[A] 1...c2[d] 2.Nf4#[C] 1...d1Q/d1R/d1B/d1N 2.Q:d1# but 1...Ke2[a]!
