Correct answer: Nc31...Ke5[a]/Nd6/[б]//Ne3/N:b2/[б]//Nb6/[б]//Na3/[б]/ 2.Bf6#[A] 1...Ne5[c] 2.Be3#[Б] 1.Ne7? (2.Qd5#) 1...Ke5[a]/Nd6/[б]//N: