Correct answer: c51...d6 2.Qe3# 1...Bd4 2.Qh2# 1.Ke7?? (2.Qd6#/Qe3#) 1...d5 2.Qe3# 1...Bc1 2.Qd6# 1...Bd4 2.Qh2#/Qg5# but 1...Ba3+!
