Correct answer: f71...d6[a] 2.Qb2#[A] 1...N:f6/[б]/ 2.Q:f6#[Б] 1...Rf3 2.R:e4# 1.Q:c5? (2.d6#) 1...d6[a] 2.Qd4#[D] 1...N:f6/[б]//Ne7[c] 2.Qe7#[C] 1...R