Correct answer: Nc71...Be6[a] 2.Qh2#[A] 1...Bf6/[б]//Bf8[c] 2.Q:f6#[Б] 1...g4[d] 2.Qe3#[C] 1...Bf7 2.N:f7# 1...Bd8 2.Q:d6# 1.R:b7? zz 1...Be6[a] 2.<
