Correct answer: Nc4+1...Kf5[a]/Bd5[c] 2.Nd4#[A] 1...Kd5/[б]/ 2.Nf4#[Б] 1...Nh3[d]/Nh7[d]/Nf3[d]/Nf7[d]/Nge4[e] 2.Bf7#[C] 1...Nd3[f]/Nd7[f]/Nce4[g]