Correct answer: Qc11...Be5+[a] 2.K:e5#[A] 1...Be7+/[б]/ 2.K:e7#[Б] 1...b5 2.a:b5# 1.Qh1?? (2.Re3#/Re2#/Re1#/Re5#/Re6#/Re7#/Ree8#/R:d4#/Rf4#/