Correct answer: Qe81...d2[a] 2.Qc2#[A] 1...b3 2.Bc5#/B:b6# 1.Qa1? (2.Qh1#) 1...d2[a] 2.Qb1#[Б] 1...e:d4/[б]/ 2.Q:d4#[C] but 1...e:d5! 1.Qc6[D]? (2.R:d6#[E]) 1