Correct answer: Nf41...Bf4[a] 2.Nd4#[A]/Be4#[Б] 1...Bf6/[б]/ 2.Qe4#[C]/Be4#[Б] 1...Bg3/Bg7/Bh8/Bd4/Bc3/Bb2/Ba1/Bd6/Bc7/Bb8 2.Be
