Correct answer: B:f31...Kc1[a] 2.Qc2#[A] 1...Bd3/[б]/ 2.Qb4#[C] 1...Be4[c]/Bf5[c]/Bg6[c]/Bh7[c] 2.Qe3#[Б] 1...Bc2/Ba2 2.Qe3#[Б]/Q:c2#[A] 1.Be
