Correct answer: Qc71.Qa7? (2.Qa3#) 1...Kb2[a] 2.Qa2#[A] 1...Kb4/[б]/ 2.Qa4#[Б] but 1...Nc3! 1.Qd6?? (2.Qa3#) 1...Kb2[a] 2.Qb4# but 1...Nc3!
